1/8x^2-1/4x=1/2

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Solution for 1/8x^2-1/4x=1/2 equation: 


x in (-oo:+oo)

(1/8)*x^2-((1/4)*x) = 1/2 // - 1/2

(1/8)*x^2-((1/4)*x)-(1/2) = 0

(1/8)*x^2+(-1/4)*x-1/2 = 0

1/8*x^2-1/4*x-1/2 = 0

DELTA = (-1/4)^2-(-1/2*1/8*4)

DELTA = 5/16

DELTA > 0

x = ((5/16)^(1/2)+1/4)/(1/8*2) or x = (1/4-(5/16)^(1/2))/(1/8*2)

x = 4*((5/16)^(1/2)+1/4) or x = 4*(1/4-(5/16)^(1/2))

x in { 4*(1/4-(5/16)^(1/2)), 4*((5/16)^(1/2)+1/4) }

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